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(F)=144-16F^2
We move all terms to the left:
(F)-(144-16F^2)=0
We get rid of parentheses
16F^2+F-144=0
a = 16; b = 1; c = -144;
Δ = b2-4ac
Δ = 12-4·16·(-144)
Δ = 9217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{9217}}{2*16}=\frac{-1-\sqrt{9217}}{32} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{9217}}{2*16}=\frac{-1+\sqrt{9217}}{32} $
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